India A needs six wickets for a win

Chasing 159, Australia A was four down for 59 at stumps on day three. India A needs six more wickets to win the unofficial four-day game in Brisbane.

jayant yadav, india a, australia a

Jayant Yadav, coming in at eight, top-scored with 46.   -  PTI

Twelve wickets fell on a rain-hit day as Australia A found itself 100 runs adrift of victory against India A on the third day of the first unofficial four-day match at the Allan Border Field here today.

Chasing 159, Australia A was four down for 59 at stumps. India A needs six more wickets to win.

After managing a two-run first-innings lead, India A started the day on 44/2 but collapsed to 156. Discounting No. 8 Jayant Yadav's 46, the score would've been dismal.

Batting under overcast conditions, India lost overnight batsman Manish Pandey in the ninth ball of the day.

Shreyas Iyer, captain Naman Ojha and Karun Nair followed suit in quick succession, before Jayant, coming in at 90 for six, steadied the ship.

Jayant was the last man dismissed, caught off medium-pacer Chadd Sayers in the last ball of the 48th over. He faced 75 balls for his 46 and struck eight fours.

For Australia A, Daniel Worrall, David Moody and Chadd Sayers took three wickets each, while legspinner Mitchell Swepson accounted for Thakur.