Harinder Pal wins South Australian Open title

The Indian beat Rhys Dowling of Australia 11-8, 12-10, 11-4 in the final.

Published : Jul 08, 2017 12:50 IST , Adelaide

Harinder Pal Singh Sandhu had defeated top seed Piedro Schweertman in the semifinals.
Harinder Pal Singh Sandhu had defeated top seed Piedro Schweertman in the semifinals.
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Harinder Pal Singh Sandhu had defeated top seed Piedro Schweertman in the semifinals.

India’s Harinder Pal Singh Sandhu beat Rhys Dowling of Australia 11-8, 12-10, 11-4 in the final to clinch the South Australian Open squash title, here on Saturday.

Sandhu was down 1-7 after winning the first game comfortably as the Australian fought back strongly. He mounted a comeback to win the game 12-10. The third game was a no-contest.

He had on Friday upset top-seed Piedro Schweertman of the Netherlands 11-9, 14-12, 7-11, 11-9 in the semifinal of the PSA World Tour event. “It has been a tough week as playing in cold climates is never easy. I have been to Australia a couple of times and it feels good to win a PSA tournament here for the first time,” Sandhu said after the triumph.

“Had a tough semifinal with the top seed and managed to stay strong and get the win. And, just stayed composed and focused [on Saturday],” he added.

It was Sandhu’s eighth title at the PSA level and the third this season after winning two in Malaysia in the month of May. He had reached the quarterfinals of the Asian Individual Squash Championship in Chennai in April.

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