WI vs India: Rohit Sharma needs four sixes to surpass Chris Gayle

With four sixes, the opener will leapfrog Gayle to take the lead among batsmen with the most number of sixes in Twenty20 Internationals.

Rohit Sharma is riding the crest of a wave, having scored five centuries in the recent World Cup.   -  AP

India’s Rohit Sharma will surpass Chris Gayle to take the lead among batsmen with the most number of sixes in Twenty20 Internationals if he hits four sixes in the first of two T20Is against West Indies here on Saturday.

In his career, Rohit has so far struck 102 sixes in 94 T20Is. Gayle tops the list with 105 in 58 outings.

Gayle is followed by Martin Guptill; the Kiwi has smashed 103 sixes in 76 matches.

Gayle to miss out

The 39-year-old Gayle will not get a chance to add to his tally as he will not feature in the three-match series. Gayle will, however, be part of the subsequent One-Day International (ODI) series.

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Rohit is already the highest run-getter in the format. He has 2,331 runs at an average of 32.37, with four centuries and 16 half-centuries.

Rohit will enter the series on a high, having scored five centuries in the ICC World Cup 2019.